Ask question

Ask question

All categories

3 years ago

14

Which of the following equations are equivalent to-2m-5m-8 #-(-7) + m?D-15m-4md:7m-8-rn-4□-3m-8-4-m□m-4.7m-8-8.7m- 4-m□-8.3m-4-m

1 answer:

Readme [11.4K]3 years ago

4 0

-2m - 5m - 8 = 3 + (-7) + m
-7m - 8 = 3 - 7 + m
-7m - 8 = m - 4 <=== here is one

m - 4 = -7m - 8 <=== another one
-8 - 7m = -4 + m <== and another one

You might be interested in

The distance between points A and B is 15. The coordinates of point A are (1, 18) and the

wel

Answer:

9 and 27

Step-by-step explanation:

let me know if you want an explanation

6 0

1 year ago

A parallelogram has a base of 9 inches and a height of 11 inches. What is the area?

Margaret [11]

11 x 9 = 99

The area is 99 inches.

5 0

3 years ago

Read 2 more answers

Valeria is playing with her accordion. The length of the accordion A(t)A(t)A, left parenthesis, t, right parenthesis (in \text{c

ikadub [295]

Answer:

−6cos( π/3 t)+21

Step-by-step explanation:

8 0

3 years ago

Convert x = 4 to polar form

dezoksy [38]

Answer: r = 4 sec θ

Explanation: Using: x = r cos θ then r cos θ = 4 ⇒ r = 4 cos θ = 4 sec θ

4 0

3 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago