1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nonamiya [84]
3 years ago
5

A group of friends wants to go to the amusement park. They have $180.50 to spend on parking and admission. Parking is $19.50, an

d tickets cost $23 per person, including tax. Write and solve an equation which can be used to determine pp, the number of people who can go to the amusement park.
equation:
answer p:
Mathematics
1 answer:
AleksAgata [21]3 years ago
4 0

a.

The required equation is  23p + 19.50 = 180.50

Let p represent the number of people who can go to the amusement park.

Since the ticket costs $23 per person, the total amount paid for ticket is rate × number of person = $23 × p = 23p.

Since we pay $19.50 for parking, the total amount spent is T = 23p + 19.50

Since the total amount equals $180.50. T = 180.50

So, 23p + 19.50 = 180.50

The required equation is  23p + 19.50 = 180.50

b.

Solving 23p + 19.50 = 180.50, we have

23p = 180.50 - 19.50

23p = 161

p = 161/23

p = 7

So, the number of people who can go to the amusement park is 7.

Learn more about linear equations here:

brainly.com/question/24307397

You might be interested in
What number multiples to -12 and adds to 4 (factoring: diamond method)
Marizza181 [45]

Answer: - 2 and 6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the length of BC ?<br>​
galben [10]
The answer is c.

Since a^2+b^2=c^2, b^2=c^2-a^2 thus,
16=4-b^2= srt. of 12
7 0
3 years ago
Read 2 more answers
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

H_0: The true average penetration is 50 mils

H_a: The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the <em>level of confidence</em> is α = 0.05 then the z_\alpha score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)

The z-score associated with this test is

z=\frac{\bar x-\mu}{s/\sqrt{n}}

where

\bar x = <em>mean of the sample</em>

\mu = <em>average established by the specification</em>

s = <em>standard deviation of the sample</em>

n = <em>size of the sample</em>

Computing this value of z we get z = 3.42

Since z >z_\alpha we can conclude that the sample has not met the required specification.

5 0
4 years ago
5x-8=2x+25 help help
Maurinko [17]
The answer would be x=11
7 0
3 years ago
What is the name of the song 50 points and brainliest.
solong [7]

Answer:

Butterflies

Step-by-step explanation:

Thanks

6 0
3 years ago
Other questions:
  • If 1,000 students take a test that has a mean of 40 minutes, a standard deviation of 8 minutes, and is normally distributed, how
    15·2 answers
  • Part 1- If 10 is 20% of a value, what is 50% of the value?
    13·1 answer
  • Find the perimeter for this<br> whoever gets it right gets 100 pts
    13·2 answers
  • Marco bought 5 gallons of gasoline for $17.70.
    7·2 answers
  • What L is alternate interior at L6?<br><br> A. L3<br> B. L5 <br> C. L1<br> D. L4
    12·1 answer
  • If f(x)=l 2x-4 l, find f(-7).
    15·1 answer
  • A train travels 360 km at a uniform speed, if speed has been increased it will take one hour less for the same journey then find
    14·2 answers
  • Thực hiện phép tính toán sau :
    8·1 answer
  • Can someone help me?
    12·1 answer
  • Evaluate: m2•m3 helppppppppppppppoo
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!