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Gre4nikov [31]
2 years ago
11

The weight of corn chips dispensed into a 14-ounce bag by the dispensing machine has been identified as possessing a normal dist

ribution with a mean of 14.5 ounces and a standard deviation of 0.2 ounce. suppose 100 bags of chips are randomly selected. find the probability that the mean weight of these 100 bags exceeds 14.6 ounces.
Mathematics
1 answer:
mamaluj [8]2 years ago
7 0
The probability that a normally distributed dataset with a mean, μ, and statndard deviation, σ, exceeds a value x, is given by

P(X\ \textgreater \ x)=1-P(X\ \textless \ x)=1-P\left(z\ \textless \  \frac{x-\mu}{\frac{\sigma}{\sqrt{n}}} \right)

Given that t<span>he weight of corn chips dispensed into a 14-ounce bag by the dispensing machine is a normal distribution with a mean of 14.5 ounces and a standard deviation of 0.2 ounce.

</span>If <span>100 bags of chips are randomly selected the probability that the mean weight of these 100 bags exceeds 14.6 ounces is given by

P(X\ \textgreater \ 14.6)=1-P\left(z\ \textless \  \frac{14.6-14.5}{\frac{0.2}{\sqrt{100}}} \right) \\  \\ =1-P\left(z\ \textless \  \frac{0.1}{\frac{0.2}{10}} \right)=1-P\left(z\ \textless \  \frac{0.1}{0.02} \right) \\  \\ =1-P(z\ \textless \ 5)=1-1=0

Therefore, the probability that </span><span>the mean weight of these 100 bags exceeds 14.6 ounces is</span> 0.

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\\ \sf\longmapsto RElative\:Frequency(Green)

\\ \sf\longmapsto RF(Green)=\dfrac{28}{14+28+28}

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