the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
A. Is the right answer I think I have e does this one before back in5th so I’m sure it’s A.
Answer:
15/4 and 45/4
Step-by-step explanation:
Let x and y be the numbers
x = 3y
x+ y = 15
Substitute the first equation in to the second equation
3y+y = 15
4y = 15
y = 15/4
x = 3(15/4)
x = 45/4
The two numbers are 15/4 and 45/4
Change each mixed fraction to improper
3 2/5 = 15/5 + 2/5 = 17/5
9 1/10 = 90/10 + 1/10 = 91/10
Find a common denominator. Multiply 2 to both numerator and denominator of 17/5
17/5(2/2) = 34/10
34/10 + 91/10 = 125/10
125/10
Simplify. Divide
125/10 = 12.5
12.5 is your answer
hope this helps
