The initial dimenssions of the park lot are:
length: 140 ft
width: 90 ft
initial area: 140 * 90 = 12,600 ft^2
Area increased 29% = 12,600 * 1.29 = 16,254 ft^2
width of the strips: x
New length: 140 + x
New width: 90 + x
New area: (140+x)(90+x) = 16,254
Solution of the equation:
12600 + 230x + x^2 = 16254
=> x^2 + 230x - 3654 = 0
Use the quadratic formula.
x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =
x = 14.92
The other solution is negative so it is discarded.
Answer: 15 ft
Answer: (3,inf)
(-inf,3)
Step-by-step explanation:
Answer:
a .8
b .03
c .125
d 125.0
Step-by-step explanation:
The maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper is 512cm³.
<h3>How to calculate the volume?</h3>
From the information, when the side of 1cm are cut, this will become an open box. The volume will be:
= 18 × 18 × 1
= 324cm³
Also, when 2cm is cut, the volume will be:
= 16 × 16 × 2
= 512cm³
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Answer:
A
Step-by-step explanation:
A is the less complicated one and the simplest but also the most efficient and the one that makes the most sense.
