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2 years ago

Can i get some help :

Mathematics

2 answers:

Lyrx [107]2 years ago

8 0

Answer:

t<28 Tia ran the race under 28 seconds

t>28 The temperature is warmer than 28°F

t<29 Tony is younger than 29 years old

t>29 The table is heavier than 29 kilograms

Step-by-step explanation:

the first sentence does not apply

Hope this helps

Tom [10]2 years ago

5 0

Answer:

sorry i dont under stand it either would it be ok if i repost this

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susan is driving to mount shasta .on her map she is a distance of 7 inches away .the scale of the map is 1/2 inch=50 miles.how f

DochEvi [55]

Answer:

700 miles

Step-by-step explanation:

Given:

Scale of the map is $\frac{1}{2}\textrm{ in}=50\textrm{ mi}$

∴ $1\textrm{ in}= \frac{50}{\frac{1}{2}}=50\times 2=100\textrm{ mi}$

Distance of Susan from mount Shasha on the map is 7 inch.

Therefore, Number of miles = $7\times 100=700\textrm{ mi}$

Hence, Susan must travel 700 miles to reach her destination.

6 0

3 years ago

Subtract. Simplify, if possible.<br> 5/8<br> -<br> * 2 1 / 2 - 3

Nat2105 [25]

$2\frac{1}{2} - \frac{5}{8}$

Convert the mixed number to an improper fraction:

$\frac{5}{2} - \frac{5}{8}$

Subtract the fractions to get your final answer:

$\frac{15}{8}$

8 0

3 years ago

The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0

STatiana [176]

Answer:

The marginal-revenue equation is $R'(x)=0.1226x+1.1584$ .

The marginal revenue for the production of 200,000,000 bushels is $R'(x)=1.4036$ .

The marginal revenue for the production of 650,000,000 bushels is $R'(x)=9.1274$ .

Step-by-step explanation:

The derivative $R'(x)$ of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, $R(x) = 0.0613x^{2} +1.1584x+2.4813$ . Therefore, the marginal revenue function is

$R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584$