Which statement best explains why magnesium and chlorine combine in a 1 to 2 ratio.

In a parking lot, 20% of the vehicles are trucks

vovangra [49]

Well there are 18 trucks in the parking lot. So there are 12 cars

4 0

3 years ago

While performing a physical examination on Denny French, Dr. Giles uses what to examine Denny's eyes

valkas [14]

While performing a physical examination on Denny French, Dr. Giles used an ophthalmoscope to examine Denny's eyes.

<h3>What is a disease?</h3>

A disease refers to any harmful and abnormal deviation of the body or body parts such as the eyes of a living organism from its normal structure or functional state due to the actions of pathogens, and it's typically accompanied by certain signs and symptoms.

<h3>What is an ophthalmoscope?</h3>

An ophthalmoscope can be defined as a type of instrument that is designed and developed to be used by an ophthalmologist to physically examine the interior of a patient's eye.

In this context, we can infer and logically deduce that while performing a physical examination on Denny French, Dr. Giles used an ophthalmoscope to examine Denny's eyes.

Read more on ophthalmoscope here: brainly.com/question/25800311

#SPJ1

8 0

2 years ago

Nombra la.unica escuela SUNY donde puedes obtener un certificado en auto autoedicion <br>

bixtya [17]

Hummmmmmmm??????!!!!!!

3 0

3 years ago

A 13-year-old adolescent is seen in the office and appears very anxious. For the past 2 weeks, the adolescent has had some muscl

Sophie [7]

Low levels of calcium in the blood (also known as: hypocalcemia)

7 0

3 years ago

very far from earth (at r=[infinity]), a spacecraft has run out of fuel and its kinetic energy is zero. if only the gravitationa

melisa1 [442]

By considering the conservation of energy, the speed V of the spacecraft when it eventually crash into the earth and its distance from the center of the earth is r are 11172.6 m/s and 3294.6 m/s respectively.

Given that, r is at infinity when a spacecraft has run out of fuel and its kinetic energy is zero. if only the gravitational force of the earth were to act on the spacecraft would eventually crash into the earth.

Where

Mass of the earth $m_{e}$ = 5.97 × $10^{24}$ kg

Radius of the earth $R_{e}$ = 6.38 × $10^{6}$ m

G = 6.67 x $10^{-11}$ N $m^{2}kg^{-2}$

a.) Since the spacecraft is primarily moving through the near vacuum of space, the speed V of the spacecraft when it eventually crash into the earth can be calculated by considering the conservation of energy.

The total initial energy = total final energy.

$E_{i} = E_{f}$

$K.E_{i}$ + $U_{i}$ = $K.E_{f}$ + $U_{f}$

where $K.E_{i}$ = 0

-G $m_{e}$ m/(r + $R_{e}$ ) = 1/2m $V^{2}$ + ( -G $m_{e}$ m)/ $R_{e}$

mass of the spacecraft will cancel out

G $m_{e}$ /(r + $R_{e}$ ) = 1/2 $V^{2}$ + ( -G $m_{e}$ )/ $R_{e}$

G $m_{e}$ /(r + $R_{e}$ ) = 0 since r is at infinity.

0 = 1/2 $V^{2}$ + ( -G $m_{e}$ )/ $R_{e}$

Substitute all the parameters into the equation above.

0 = 0.5 $V^{2}$ + ( -6.67 x $10^{-11}$ x 5.97 x $10^{24}$ )/6.38 x $10^{6}$

0.5 $V^{2}$ = 62,413,636.36

$V^{2}$ = 62,413,636.36 / 0.5

$V^{2}$ = 124,827,272.7

V = $\sqrt{124,827,272.7}$

V = 11172.6 m/s

b.) Given that the distance from the earth r = x( $R_{e}$ )

That is,

r = 11.5 x 6.38 x $10^{6}$

r = 73,370,000 m

To find the spacecraft's speed when its distance from the center of the earth is r, we will use the same formula. That is,

$K.E_{i}$ + $U_{i}$ = $K.E_{f}$ + $U_{f}$

0 = 1/2 $V^{2}$ + ( -G $m_{e}$ )/r

Substitute all the parameters into the formula

0 = 0.5 $V^{2}$ + ( -6.67 x $10^{-11}$ x 5.97 x $10^{24}$ )/ 73,370,000

0.5 $V^{2}$ = 5427272.727

$V^{2}$ = 10854545.45

V = $\sqrt{10854545.45}$

V = 3294.6 m/s

Therefore, the speed V of the spacecraft when it eventually crash into the earth and its distance from the center of the earth is r are 11172.6 m/s and

3294.6 m/s respectively.

Learn more about gravitation potential here: brainly.com/question/940770

7 0

3 years ago