Answer and Explanation:
6.2125 g of Na₂SO₄ is needed to prepare 350 mL of a solution.
You have to know that molarity is a measure of the concentration of a solute that is defined as the number of moles of solute that are dissolved in a certain volume.
number of moles of solute= 0.125 M×0.350 L=0.04375
142 g/mole is the molar mass of Na₂SO that's the mass of one mole of the compound and the amount of mass that contains 0.04375 moles. Mass= 0.04375 moles× 142 g/mole therefor mass= 6.2125 g.
So, 6.2125 g of Na₂SO₄ is needed to prepare 350 mL of a solution having a sodium ion of 0.125 M
Please let me know if I did anything wrong. I'm pretty sure I'm right but I cant always be sure.
