I’m just here to share positive
You got this!!
I believe in you:)
Dude, what kind of question is this??? Here's my best shot.
If they start at the 32-mile mark, then the we can use 32 as the intercept. 50 can be the change in position over time, so
y=50x+32 (?)
Answer:
Only choices C and D are solutions
Step-by-step explanation:
6x + 3y = -15
y = -2x - 5
6x + 3y = -15
6x + 3(-2x - 5) = -15
6x - 6x - 15 = -15
0 = 0
Since 0 = 0 is a true statement, both equations of this system are the same equation and represent a single line on the coordinate plane.
We need to check each choice in just one equation.
Let's use the second equation.
y = -2x - 5
A.
(2, 7)
7 = -2(2) - 5
7 = -4 - 5
7 = -9 False
Not a solution
B.
(5, 0)
0 = -2(5) - 5
0 = -10 - 5
0 = -15 False
Not a solution
C.
(-3, 1)
1 = -2(-3) - 5
1 = 6 - 5
1 = 1 True
Solution
D.
-13 = -2(4) - 5
-13 = -8 - 5
-13 = -13 True
Solution
Answer: Only choices C and D are solutions
Y-Intercept =(−8)
Go to the graph and plot the point the point (0,−8) on the y-axis.
Then rise 4 and run 1. Plot the point (1,−4)
Then again "rise 4" and then "run" 1. Plot the point (2,0)
Well I don't know how to show work on this one.
50. 2 3/4 is between 2 and 3, three times farther from two than three. Draw a dot in approximately that locations and mark it 2 3/4.
51. 4 1/3 is between 4 and 5, twice as far from five as from four. Draw a dot and mark it 4 1/3.
