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2 years ago

Someone pls help pls I need help

Mathematics

2 answers:

EleoNora [17]2 years ago

7 0

Answer:

21

Therefore

Answer = 21

hope helps~

AlladinOne [14]2 years ago

7 0

Answer:

Step-by-step explanation:

4h + h^2

4(3) + 3^2

12 + 9

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Neach row, colour the one with more number of pictures

saul85 [17]

Answer

neach row, colour the one with more number of pictures

Step-by-step explanation:

neach row, colour the one with more number of pictures

5 0

3 years ago

Find the measure of x in each figure

uysha [10]

Answer:

x = 20

Step-by-step explanation:

The two angle are a linear pair. Their measures has a sum of 180 deg.

2x + 140 = 180

2x = 40

x = 20

7 0

3 years ago

What is the answer? Will mark the brainlest. (−5⋅3)−8k

earnstyle [38]

Answer:

-15-8k

Step-by-step explanation:

That's the best I could simplify it to. Hope it helps.

Please mark as Brainliest! :)

Have a nice day.

6 0

3 years ago

Read 2 more answers

The initial point of a⃗ is (−2,4), and its terminal point is (−5,−2). What is the value of ‖a⃗ ‖? Give your answer as a simplifi

lyudmila [28]

Answer:

$3\sqrt{5}.$

Step-by-step explanation:

It is given that the initial point of $\vec{a}$ is (-2,4) and terminal point is (-5,-2). So, $\vec{a}$ is defined as

$\vec{a}=(-5-(-2))\hat{i}+(-2-4)\hat{j}$

$\vec{a}=(-5+2)\hat{i}+(-2-4)\hat{j}$

$\vec{a}=-3\hat{i}-6\hat{j}$

The magnitude of $\vec{v}=a\hat{i}+b\hat{j}$ is

$|\vec{v}|=\sqrt{a^2+b^2}$

The magnitude of $\vec{a}$ is

$|\vec{a}|=\sqrt{(-3)^2+(-6)^2}$

$|\vec{a}|=\sqrt{9+36}$

$|\vec{a}|=\sqrt{45}$

$|\vec{a}|=3\sqrt{5}$

Modulus of magnitude is

$||\vec{a}||=|3\sqrt{5}|=3\sqrt{5}$

So, the magnitude of $\vec{a}$ is $3\sqrt{5}.$

8 0

3 years ago

What is 1/4 divided by 7/10

VMariaS [17]

It would be: 1/4 / 7/10
We can re-write it as : 1/4 * 10/7 = 10/28 = 5/14

In short, Your Answer would be 5/14

Hope this helps!

5 0

3 years ago

Read 2 more answers