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3 years ago

Owen prepared 25 kilograms of dough after working 5 hours in the bakery.

Mathematics

1 answer:

Licemer1 [7]3 years ago

5 0

It would be 10 hours. 25 times 2 is equal to 50 and so you would times 5 by 2 and get 10 hours

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andy is scuba diving he starts at sea level and then descends 10 feet in 2 1/2 minutes. how would you represent andy’s descent a

UNO [17]

Answer:

4 feet/minute

explanation:

The rate of descent = (10 feet)/(2.5 mn) = 4 ft/min

6 0

3 years ago

Hey can you please help me with 8 and 10 :)

insens350 [35]

8) So remember the sum of all angles inside a triangle is equal to 180°. We first want to figure out the angle below the 110°.

A straight line is 180° so if we do 180 - 110 we get 70° therefore the angle below the 110° is 70°.

So we now know two angles in the triangle, 70° and 80°. Add these and we get 150°. Now we can determine the final angle (the one labelled (2x - 6)) which will be 30°.

So let’s make it into an equation:

2x - 6 = 30

Add 6 to both sides to isolate 2x:

2x = 36

Divide by 2 to get the value of x:

x = 18

10) Since the sum of all angles in a triangle is 180, and there are only 3 angles, we can determine A easily.

B = 10°
C = 160°

So to determine A:

180 - 160 - 10

Which gives us 10

Therefore A = 10°.

So the answers:

8) x = 18
9) A = 10°

I hope this helps you!!

4 0

2 years ago

( YOU’LL GET MARKED BRAINLIEST !! )

Mariulka [41]

Answer:

1/4

Step-by-step explanation:

The answer to this question is the amount of blue gummy bears over the total amount of gummy bears. This is 15/60 or 1/4.

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

15:40:25 in simplest form

Contact [7]

Answer:

the answer is 3:8:5

Step-by-step explanation:

This is because it says Apple, coconut, and orange, but you put orange, apple, and coconut

3 0

3 years ago