Question

How to solve an equation using quadratic formula

Answer 1

Answer:

${ \rm{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }}$

Answer 2

Answer:

The roots of the quadratic equation

$ax {}^{2} + bx + c = 0,a≠0,$

are given by the quadratic formula:

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

Let's have an example.

Consider the quadratic equation:

$Solve \: 2x^2-4x-30=0$

$a=2,b=-4 \: and \: c=-30$

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{ 4± \sqrt{ { - 4}^{2} - 4 \times 2 \times - 30 } }{2 \times 2}$

$x = \frac{ 4± \sqrt{ {16} + 240} }{4}$

$x = \frac{ 4± }{4} = \frac{4±16}{4}$

$x_{1} = \frac{4 + 16}{4} = 5 \: \: \: \: \: \: \: \: x_{2} = \frac{4 - 16}{4} = - 3$

Step-by-step explanation:

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