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denis-greek [22]
2 years ago
5

8^6 * 8^4 Rewrite the expression in the form 8^n

Mathematics
1 answer:
Vlad [161]2 years ago
6 0
8^6*8^4 is 1073741824 I think that is 8^10
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2 years ago
What is the quotient of 2 1/5 ÷ 6 3/5 <br><br>A. 1/3<br><br>B. 3/4<br><br>C. 24/35<br><br>D. 2/3​
zepelin [54]

Answer:

A.1/3

Step-by-step explanation:

on the picture

if it's helpful ❤❤❤

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7 0
2 years ago
The answer for your question is a 1;3 because 16/48=1/3 or 1:3.
tiny-mole [99]
1:3 = 16/48 and 1/3.

Have a nice day! :D
4 0
3 years ago
A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

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3 years ago
The modified accelerated cost recovery system (MACRS):
ZanzabumX [31]

bahala kau ha ha. Matt wahak

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2 years ago
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