Question

Initially, there were only 197 weeds at a park. The weeds grew at a rate of 25% each week. The following function represents the weekly weed growth: f(x) = 197(1. 25)x. Rewrite the function to show how quickly the weeds grow each day and calculate this rate as a percentage. F(x) = 197(1. 25)7x; grows at a rate of approximately 2. 5% daily f(x) = 197(1. 257)x; grows at a rate of approximately 4. 77% daily f(x) = 197(1. 03)x; grows at a rate of approximately 0. 3% daily f(x) = 197(1. 03)7x; grows at a rate of approximately 3% daily.

Answer 1

The function that shows how quickly the weeds grow each day is $f(x) = 197(1. 25)^{7x}$ and the weed grows at a rate of approximately 3% daily

The standard form of an exponential function is given as y = ab^x

Given the exponential function that shows the rate at which the weed grew each day expressed as g(x) = 197(1. 25)^x

• x is the time in weeks

• Since there are 7 days in a week, the time will in the day will be expressed as 7x where x is in days.

Substitute x as 7x in the given exponential function to have:

$f(x) = 197(1. 25)^{7x}$

If the growth rate was 25% each week, then;

0.25 = 7 days

x = 1 day

7x = 0.25

x = 0.25/7

x = 0.0357

Hence the weed grows at a rate of approximately 3% daily

Learn more on exponential function here: brainly.com/question/12940982