If John charge $12 then he has 14 students, and he gets $ 14*12,
If he increases on $2(12+2) , he loses 1 student (14-1), gets (12+2)*(14-1)
if he increases on he loses 2 students (14-2) gets (12+2*2)(14-2)
2+2 (12+2*2)
if he increases 2*3 he loses 3 students, (14-3) gets (12+2*3)(14-3)
2x*3 (12+2*3)
and so on......
if he increases 2*x, he loses x students, (14-x)left, gets (12+2x)(14-x)
(12+2x)
So , his revenue in general =
(12+2x)(14-x)=12*14-12x+28x-2x²=-2x²+16x+168
<em> I think it should look like this
</em>c(x)= -2x²+16x+168
In this question, you're solving the inequality by solving for x.
Solve for x:
x + 8 < 10
<em>subtract 8 from both sides</em>
x < 2
Answer:
x < 2
Answer:
w=63
Step-by-step explanation:
1. Multiply both sides by 2
2. square both sides
At this point, you should have this:
w+1=64
Subtract 1 from both sides.
w=63
HTH, good luck :)
Answer:
1.68
Step-by-step explanation:
log723.7=2.86
multiplication in log is addition so 2.86+
log0.0667=-1.18
so 2.86+-1.18=1.68
Answer:
i think it is B, i really hope i am right and i apologize if i am not.