Answer:
The concentration of a drug in an organ at any time t (in seconds) is given by s 0.25t - 15(1 - e-t/60) if osts 20 | 15e-t/60 – 10e-(t - 20)/60 if t> 20 where c(t) is measured in milligrams per cubic centimeter (mg/cm3). (a) What is the initial concentration of the drug in the organ? 0 mg/cm3 (b) What is the concentration of the drug in the organ after 14 sec? (Round your answer to three decimal places.) x mg/cm3 38 (c) What is the concentration of the drug in the organ after 40 sec? (Round your answer to three decimal places.) mg/cm3 Need Help? | Read It
1. 4g= 37-5
⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8
2. c= 5*6
⇒ c= 30
3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.
4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0
5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17
6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7
7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9
8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8
9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0
10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24
11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3
12. x/3= 6-7
⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3
13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2
14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8
15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5
16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3
17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
⇒ v= 1.2
18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
⇒ n= 21
19. t+10= 1*4
⇒ t+10= 4
⇒ t= 4-10
⇒ t= -6
20. 3c+4= 3*5
⇒ 3c+4= 15
⇒ 3c= 15-4
⇒ 3c= 11
⇒ c= 11/3
⇒ c= 3 2/3
Hope this helps~
Answer:
Ancient Greeks
Beginning in the 6th century BC with the Pythagoreans, with Greek mathematics the Ancient Greeks began a systematic study of mathematics as a subject in its own right. Around 300 BC, Euclid introduced the axiomatic method still used in mathematics today, consisting of definition, axiom, theorem, and proof.
Step-by-step explanation:
This formula solve by discriminant (D=b^2-4ac)
