I think the answer will be A
+1,-1 and your other would be 1,1
parallel lines have the same slope
The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"
They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3
You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6
So far we have y=-5/6x + b
We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"
Replace that on the equation y=-5/6x + b and you get
-1 = (-5/6)(6) + b
-1 = -5 +b
4 = b
b = 4
We found b, or the y-intercept
Go back to the equation y = -5/6 x + b and replace this b with the b we just found
y = -5/6x + 4
R; all quadratic functions are going to have ranges and domains of *ALL REAL NUMBERS*.
Answer: 43% increase
Step-by-step explanation:
You are welcome :)
