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Zina [86]
3 years ago
12

-8(2a + 3b) + 5 (6 + -4d)

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

It would be simplified to -16a-24b-20d+30

Step-by-step explanation:

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A recipe code lasagna calls for 3 pounds of tomatoes to serve 5 people. A caterer wants to make enough lasagna to serve 110 peop
yKpoI14uk [10]

Answer:

66 pounds of tomatoes

Step-by-step explanation:

A recipe code lasagna calls for 3 pounds of tomatoes to serve 5 people. A caterer wants to make enough lasagna to serve 110 people. How many pounds of tomatoes does he neeed

From the above question:

5 people = 3 pounds of tomatoes

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Cross Multiply

5 people × x pounds = 110 people × 3 pounds

x pounds = 110 people × 3 pounds/5 people

x pounds = 66 pounds of tomatoes

4 0
3 years ago
14. the number of deer spotted in a nature preserve each day over a two week period is listed below. 32 27 15 12 42 35 46 29 38
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5 0
3 years ago
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Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x
svetlana [45]
Hello,

sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\


==============================================================
2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\

=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\

= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\

= \dfrac{1}{sin^2x*cos^2x}} 

8 0
3 years ago
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Debbie set a goal to run 6 miles. On Monday she ran 2.6 miles and on Tuesday she ran 1.75 miles. How far would Debbie need to ru
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