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levacccp [35]
2 years ago
6

Solve for f(5) f(x)=2x-4 f(5)=?

Mathematics
1 answer:
alexira [117]2 years ago
8 0

Answer:

x = 6

Step-by-step explanation:

2(5) - 4

-> 10 - 4

-> 6

-> x = 6

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S - 10,000 = 3,753<br><br>A. s = 13,573<br><br>B. s = 13,753<br><br>C. s = 10,375
Lesechka [4]

Answer:

B. s = 13753

Step-by-step explanation:

s - 10000 = 3753

To find value of s, add both sides by 10000

s - 10000 = 3753

   +10000    +10000

-----------------------------------

s = 13753

6 0
3 years ago
Square root of 9 + square root of 64?
Crank

Answer:

11...................

8 0
3 years ago
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Which equation should be used to calculate the 43rd partial sum for the arithmetic sequence.
MariettaO [177]

Answer: First Option : Sₙ= n/2(a₁ + aₙ)

Step-by-step explanation:

The nth partial sum of an arithmetic sequence or the sum of the first n terms of the arithmetic series can be defined as the sum of a finite number of term in an arithmetic sequence.

It is calculated using the formula:

Sₙ= n/2(a₁ + aₙ)

Where :

a₁ = First term

aₙ = last term

n = number of terms

6 0
2 years ago
Solve√( 7×±4 )≈2√× and the steps involved
Neporo4naja [7]
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4 0
3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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