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forsale [732]
3 years ago
5

Kevin counts 75 chicks in the hen house. He also sees more chicks outside the hen house. How can Kevin count to find how many ch

icks in all? We counted by 1s and in all there are 108 chicks. The question is: what do we know about the chicks? What do you need to find?
Mathematics
1 answer:
stellarik [79]3 years ago
8 0

What we know:

we know that there are <u>75</u> chicks in the hen house, we also know that in all there are 108 chicks

What we need to find:

we need to find out how many chicks were outside

Answer equation:

108 - 75 = 33

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Answer:

Length ≈ 31cm

Width ≈ 10cm

Step-by-step explanation:

Let -the-length-be : x\\Let-the-width-be :y\\\\According- to- the- question ; \\x = 3(y)\\x=3y ---------(1)\\2(l+w)=82\\2(x+y)=82\\2x+2y =82 --------(2)\\Substitute- the - given- value- for ; x -in - equation---(1) into -equation (2)\\2(3y)+2y =82\\6y+2y=82\\8y =82\\\frac{8y}{8} =\frac{82}{8} \\y = 10.25\\\\Substitute 10.25 -for ;y -in -eq 1\\x=3y ---------(1)\\x = 3(10.25)\\x = 30.75

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Length =31\\Width = 10\\P = ?\\P= 2(l+w)\\P = 2(31+10)\\P = 2(41)\\P= 82cm

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3 years ago
a coin is tossed 625 times and heads came up 275 times. what is the experimental probability of tossing tails
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Anand needs to hire a plumber. He's considering a plumber that charges an initia
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Complete question :

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $65 along with an

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Let H represent the whole number of hours that the plumber works.

1) Which inequality describes this scenario?

Choose 1 answer:

A. 28 + 65H < 250

B. 28 + 65H > 250

C. 65 + 28H < 250

D. 65 +28H > 250

2) What is the largest whole number of hours that Anand can afford?​

Answer:

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Number of hours Anand can afford = 6 hours

Step-by-step explanation:

Given the following information :

Initial hourly rate = $65

Hourly rate = $28

Number of hours worked (whole number) = H

Maximum budgeted amount to spend = $250

Therefore ;

(Initial charge + total charge in hours) should not be more than $250

$65 + ($28*H) < $250

65 + 28H < 250

Number of hours Anand can afford :

65 + 28H < 250

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