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2 years ago

Evaluate the expression 5 /6 + -3 /5

Mathematics

1 answer:

Karo-lina-s [1.5K]2 years ago

4 0

Step-by-step explanation:

$\frac{7}{30}$

$\frac{5}{6} + ( - \frac{3}{5} ) \\ lcm = 30 \\ \frac{25 + ( - 18)}{30} = \frac{7}{30}$

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Hello,
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3 years ago

What is the equation in point-slope form for the line parallel to y = -2x - 4 that contains J(-8, 1)?

Aleksandr [31]

The answer is letter b. y - 1 = 2(x + 8)
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3 years ago

Please help and explain how to do this

Mnenie [13.5K]

Answer:

4√3

Step-by-step explanation:

The distance formula applies. It tells you ...

distance = √((x2 -x1)² +(y2 -y1)²)

Filling in the given values, you have ...

distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)

= √((-4√2+4√2)² +(2√3 +2√3)²)

= √(0 + (4√3)²)

distance = 4√3

___

We make use of the fact that ...

$a\sqrt{b}=\sqrt{a^2b}\\\\\sqrt{32}=\sqrt{16\cdot 2}=4\sqrt{2}\\\\2\sqrt{3}=\sqrt{2^2\cdot 3}=\sqrt{12}$

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3 years ago

Write an equation in point-slope form for the line that has the given slope m

meriva

Answers:

13) y + 2 = 1/4x

14) y - 1 = -2x

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3 years ago

How do I factor out a constant before factoring out a quadratic? <br>Factor completely: 3w^2-3w-90

pantera1 [17]

$3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5$

$w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)$

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3 years ago