2 years ago

What is the value of x? Enter your answer in the box.

Mathematics

1 answer:

jolli1 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

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Kazeer [188]

Answer:

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Step-by-step explanation:

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3 years ago

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A circle has a radius of \sqrt{13}√ 13 square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le

timofeeve [1]

Answer: The equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

Step-by-step explanation: We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

$(x-h)^2+(y-k)^2=r^2.$

In the given circle,

radius, r = √13 units and center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

$(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.$

Thus, the equation of the circle is

$x^2+y^2+18.6x-8.2y+90.3=0.$

7 0

3 years ago

Can somone help me please?

vova2212 [387]

It's the second answer

6 0

3 years ago

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I need help on the question up here

vovangra [49]

2x + 4a = 10

2x = 10 - 4a

x = 5 - 2a

8 0

3 years ago

Can I get some help on this pls

defon

2.) 3
3.) 3723
4.) 1512
5.)4692
6.)5525
7.) 760
8.) 696

6 0

3 years ago