Write the number 33×10^-3 in scientific notation

What is the area of a triangle that has a height of 12 feet and a base length of 6 feet? 24 feet2 36 feet2 48 feet2 72 feet2

Kaylis [27]

It is 36 feet
A=1/2bh
a=1/2*12*6
a=6*6
a=36feet squared
hope this helps!

8 0

3 years ago

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SOMEONE ANSWER PLEASE The trapezoid below is made up of a square and a triangle The total area of the trapezoid

vladimir2022 [97]

Solution:

Note that:

Area of trapezoid = Area of triangle + Area of square = 575 m²
Area of triangle = 32.5 m²
Area of square = s²

Finding the area of the square:

32.5 + Area of square = 575 m²
=> Area of square = 575 - 32.5
=> Area of square = 542.5
=> s² = 542.5
=> s = √542.5 ≈ 23.29

The length of the square is 23.29 meters.

4 0

2 years ago

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0.624 in expanded form

Tpy6a [65]

The correct answer is:

0.6 + 0.02 + 0.004

Explanation:

To write a number in expanded form, we use place value. In this number, 6 is in the tenths place; that makes its value 6(0.1) = 0.6.

2 is in the hundredths place; that makes its value 2(0.01) = 0.02.

4 is in the thousandths place; that makes its value 4(0.001) = 0.004.

Together, we get a sum of 0.6+0.02+0.004.

3 0

3 years ago

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What is the solution to 11=c/-5 8?

ss7ja [257]

Is it c/-58, or is it c/-5 blank 8?

7 0

3 years ago

An auto company claims that the fuel efficiency of its sedan has been substantially improved. A consumer advocate organization w

zzz [600]

Answer:

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.983 -0}{\frac{1.685}{\sqrt{12}}}=2.021$

$df=n-1=12-1=11$

$p_v =P(t_{(11)}>2.021) =0.0342$

If we compare the the p value with the significance level provided $\alpha=0.1$ , we see that $p_v < \alpha$ , so then we can reject the null hypothesis. and there is a significant increase in the miles per gallon from 2017 to 2019 at 10% of significance.

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation :

x=test value 2017 , y = test value 2019

x: 28.7 32.1 29.6 30.5 31.9 30.9 32.3 33.1 29.6 30.8 31.1 31.6

y: 31.1 32.4 31.3 33.5 31.7 32.0 31.8 29.9 31.0 32.8 32.7 33.8

Solution to the problem

The system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x \leq 0$

Alternative hypothesis: $\mu_y -\mu_x >0$

Because if we have an improvement we expect that the values for 2019 would be higher compared with the values for 2017

The first step is calculate the difference $d_i=y_i-x_i$ and we obtain this:

d: 2.4, 0.3, 1.7,3,-0.2, 1.1, -0.5, -3.2, 1.4, 2, 1.6, 2.2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{11.8}{12}=0.983$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.685$

We assume that the true difference follows a normal distribution. The 4th step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{0.983 -0}{\frac{1.685}{\sqrt{12}}}=2.021$

The next step is calculate the degrees of freedom given by:

$df=n-1=12-1=11$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_{(11)}>2.021) =0.0342$

If we compare the the p value with the significance level provided $\alpha=0.1$ , we see that $p_v < \alpha$ , so then we can reject the null hypothesis. and there is a significant increase in the miles per gallon from 2017 to 2019 at 10% of significance.

4 0

2 years ago

Write the number 33×10^-3 in scientific notation​

Write the number 33×10^-3 in scientific notation