Answer:
m=6
x=6
Can i please have brainliest? I never get brainliest. :(
Answer:
Step-by-step explanation:
Be careful how you handle this.
f(-7) = 3(-7)^2
f(-7) = 3* 49 Notice the minus sign disappears. That's because there are 2 of them.
f(-7) = 147
Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80
![d \times 0.10 + q \times 0.25 = 4.80](https://tex.z-dn.net/?f=d%20%5Ctimes%200.10%20%2B%20q%20%5Ctimes%200.25%20%3D%204.80)
0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
Answer:
b
Step-by-step explanation:
<span>8(t + 2) - 3(t - 4) = 6(t - 7) + 8
To solve this equation, first apply the Distributive Property. The Distributive Property is defined as a(b + c) = ab + ac. We'll need to apply it three times for this equation.
8(t + 2) => 8t + 16
-3(t - 4) => -3t + 12
6(t - 7) => 6t - 42
This gives us
</span>8(t + 2) - 3(t - 4) = 6(t - 7) + 8
8t + 16 - 3t + 12 = 6t - 42 + 8
Next, combine like terms (constants with constants and variable terms with variable terms).
8t + 16 - 3t + 12 = 6t - 42 + 8
5t + 28 = 6t - 34
Now we need to get all constants on one side and all variable terms on the other side. Begin doing so by first subtracting 28 from both sides.
5t + 28 = 6t - 34
5t = 6t - 62
Subtract 6t from both sides.
5t = 6t - 62
-t = -62
Divide both sides by -1.
t = 62
Answer:
t = 62