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JulsSmile [24]
2 years ago
10

¿que es para ti la navidad?

Social Studies
1 answer:
Llana [10]2 years ago
4 0

Answer:

Para mi, la navidad es un día que puedo pasar tiempo con mi familia

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The researchers of the early years of marriage (eym) project are primarily interested in how _____ affect marital outcomes.
lesantik [10]

Answer:interested in how SOCIAL CONDITIONS affect marital outcomes.

Explanation:

Social conditions refer to those conditions which people encounter within society due to their level of education, occupation and income. Newly married couples are likely to face these conditions due to the fact that they will usually spend more on their wedding day or they are still starting off in their careers but also there is pressure to live up to those standards that are expected of them from that society but only to find that they have so much that they need to put into place , they need a house and all other basic needs so it becomes too much with a not so good job and some are still studying .

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A farmer must decide between growing peppers or growing tomatoes. Which trade off is the farmer considering?
TiliK225 [7]
Tomatoes because they are bussin and easier to grow
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3 years ago
How did the colonists protest the stamp act?
rusak2 [61]
Slogan: "No tax without representation"

Colonists protest the Stamp Act by refusing to buy British's goods.
7 0
3 years ago
Do you think political cartoons influence readers? How so?
Fittoniya [83]

Answer:

Political cartoons can be very funny, especially if you understand the issue that they're commenting on. Their main purpose, though, is not to amuse you but to persuade you. A good political cartoon makes you think about current events, but it also tries to sway your opinion toward the cartoonist's point of view.

Explanation:

4 0
3 years ago
Question 9 please both a and b
GarryVolchara [31]

a^k - b^k = (a - b)(a^{k-1} + a^{k-2}b + ... + b^{k-1})

a. Let's set a=3, b=1

3^k - 1^k = (3 - 1)(\textrm{some integer we'll call } m)

3^k = 1 + 2m

In other words 3^k is odd, i.e. 3^k has remainder 1 when divided by 2. \quad\checkmark

b. Let

k=2n, a=3, b=1

a^k - b^k = (a - b)(a^{k-1} + a^{k-2}b + ... + b^{k-1})

3^{2n} - 1^{2n} = (3 - 1 )(3^{2n-1} + 3^{2n-2} + ... + 1)

There are 2n terms in the last factor.  All the terms of the form

3^{2n-k}

are odd. So when we add up an even number of them, we get an even number, call it 2m.

3^{2n} - 1 = 2(2m)

3^{2n} - 1 = 4m

We've shown 3^{2n}-1 is divisible by four.  \quad \checkmark

Merry Christmas!

3 0
3 years ago
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