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Phoenix [80]
3 years ago
7

PLEASE HELP!!!

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0
Vertex form is
y = a {(x - h)}^{2}  + k
where (h,k) is the vertex.
We can see that the vertex of the graph is at (2,0), and that the graph opens downwards, but does not look stretched at all.
Therefore,
a = -1
h = 2
k = 0
and our vertex form equation is
y =  -  {(x - 2)}^{2}  + 0
which is answer A
sladkih [1.3K]3 years ago
4 0
<span>A. y= -(x-2)^2 its this one

</span>
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write a point-slope equation for the line that passes through the point (6,8) and is parallel to the line given by y=-5x+4
VashaNatasha [74]

Answer:

  y -8 = -5(x -6)

Step-by-step explanation:

The point-slope form of the equation for a line is generally written ...

  y -k = m(x -h)

for slope m and point (h, k).

The slope of your parallel line is the same as the slope of the reference line, -5. So your equation is ...

  y -8 = -5(x -6)

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zhuklara [117]
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Damm [24]

Answer:

\huge{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}

Step-by-step explanation:

\huge{ \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b}  +  {ab}^{2}  }  \div  \frac{ {a}^{2b} -  {ab}^{2}  }{ {a}^{2b} -  {ab}^{2}  }}

\huge{\frac{ {x}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }  \div 1}

\huge{\boxed{\green{=  \frac{ {a}^{2}  -  {b}^{2} }{ {a}^{2b} +  {ab}^{2}  }}}}

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Answer:

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\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

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\frac{1}{64}   + 64

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