Question

Please help me with this, no false answers.. Thank you!​

Answer 1

• x=30

The relationship given

$\\ \sf\longmapsto y\propto x^2$

$\\ \sf\longmapsto y=kx^2$

Now

• When y is 2 x is 4(2^2=2)
• y_1=2
• x_1=4
• x_2=30
• y_2=?

Putting direct variation rule

$\\ \sf\longmapsto x_1y_2=x_2y_1$

$\\ \sf\longmapsto 4y_2=30(2)$

$\\ \sf\longmapsto 4y_2=60$

$\\ \sf\longmapsto y_2=15$

Answer 2

The variation equation when y varies directly as the square of x is y = kx².

The value of y when x = 30 is 900k.

Definition and types of variation:

Variation establish relationship between variable. Types of variation includes

• Direct variation
• Inverse variation
• Joint variation
• Combined variation

y varies directly as the square of x , Therefore,

• y α x²
• y = kx²

where

k = constant of proportionality

Solve for y when x = 30.

Therefore,

y = kx²

y = 30²k

y = 900k

learn more on variation here:brainly.com/question/13977805?referrer=searchResults