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bekas [8.4K]
4 years ago
7

How would you find the equation of a line that is perpendicular to y = 3x + 1 and passes through point (1, -1)?

Mathematics
1 answer:
Strike441 [17]4 years ago
7 0

perpendicular means the slopes of the two lines are opposite reciprocals. Since the slope of y = 3x + 1 is "3", then the opposite reciprocal slope is \frac{-1}{3}

Next, plug in the slope (\frac{-1}{3} )and point (1, -1) into the point-slope formula: y - y₁ = m(x - x₁); where (x₁, y₁) is the point.

y - (-1) = \frac{-1}{3}(x - 1)

y + 1 = \frac{-1}{3}x + \frac{1}{3}

y = \frac{-1}{3}x + \frac{-2}{3}

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