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harina [27]
2 years ago
15

Help me please ^^ I'm getting my grades to all A's for a honerole

Mathematics
1 answer:
UNO [17]2 years ago
5 0

Answer:

A

Step-by-step explanation:

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Find the GCF of the numbers 45 and 76 using lists<br> of factors.
Marina86 [1]

Answer:

The factors of 45 are: 1, 3, 5, 9, 15, 45

The factors of 76 are: 1, 2, 4, 19, 38, 76

Then the greatest common factor is 1.

Step-by-step explanation:

There are no common factors other than 1

5 0
3 years ago
) Picture frames are produced such that the four sides of a picture frame consist of two pieces from a population whose mean len
Natali [406]

Answer:

The mean perimeter of frame = 38 cm

Step-by-step explanation:

By perimeter of a rectangle, the formula is given as:

Perimeter of rectangle = 2(A + B)

Going by the illustration in the question, the perimeter is

==> 2(32 + 44) = 152 cm.

However, we a given the mean perimeter of the frame which are:

32 and 44. We can either choose to say; each sides is (32 by 32) and (44 by 44). Or we consider it in mean/average term as given: (32 by 44).

Case 1: To obtain the mean perimeter of the frame using the first scenario, we say:

Mean perimeter = (32+32+44+44)/4 = 38 cm.

Case 2: We can simply say:

Mean perimeter = (32 + 44)/2 = 38 cm.

Graphically: Assuming that the frame is given below

                     32 cm

          ---------------------------------

         |                                      |

         |                                      |

44 cm|                                      | 44 cm

         |                                      |

         |                                      |

         |                                      |

         ----------------------------------

                       32 cm

The mean of upper frame/bars = 32 cm

The mean of side frame/bars  =  44 cm

Hence, the mean of the perimeter = (32 + 44)/2 = 38 cm

OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

3 0
3 years ago
The domain of the function f(x) = 3x3 is {2, 5}. What is the function’s range?
Sholpan [36]
The domain is {2,5} which the set containing the numbers 2 and 5. I'm assuming that the function is f(x) = 3x3<span>. So...

</span>when x = 2, f(x) = 3*23<span> = 3*8 = 24.
</span>when x = 5, f(x) = 3*53<span> = 3*125 = 375.

so this means the functions range is {24, 375}

hope this helped you out</span>
6 0
3 years ago
Rewrite each sum as a product of a gcf as a new sum 9+15
Crazy boy [7]
4 +5 = 9 and 12 + 3 =15 and there is more than this
hope I helped
7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
2 years ago
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