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jeyben [28]
2 years ago
12

CAN SOMEONE HELP ME PLEASE ASAP!

Mathematics
2 answers:
zheka24 [161]2 years ago
8 0

The answer is P and R

dlinn [17]2 years ago
8 0

Answer:

Q and R

Step-by-step explanation:

to be similar all sides must have the same scaling factor :

the factor from 2 to 8 is 4.

and the factor from 3 to 12 is also 4.

therefore, these 2 parallelograms are similar.

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Solve for x assume that lines wich appear to be tangent are tangent, please HELPP don't do it just for points please I really ne
snow_tiger [21]

Answer:

Hope It Help

Step-by-step explanation:

Brainliest Please

3 0
3 years ago
Read 2 more answers
Eliminate the parameter in the equations x = 5cos(t) – 7 and y = 5sin(t) 9. how can the rectangular equation be described?
Maksim231197 [3]

Recall that for all t,

cos²(t) + sin²(t) = 1

Now,

x = 5 cos(t) - 7   ⇒   (x + 7)/5 = cos(t)

y = 5 sin(t) + 9   ⇒   (y - 9)/5 = sin(t)

so that substituting into the identity above, we get

((x + 7)/5)² + ((y - 9)/5)² = 1

which we can rewrite as

(x + 7)²/25 + (y - 9)²/25 = 1

(x + 7)² + (y - 9)² = 25

and this is the equation of a circle centered at (-7, 9) with radius 5.

3 0
2 years ago
Solve for t.<br><br>-1(t + 8) = -7.1​
lawyer [7]
T= -0.9 is the answer
8 0
3 years ago
Un edificio proyecta una sombra de 7.5m.mientras que un arbol que mide 1.6 m de altura proyecta una sombra 1.85 M¿Cual es la alt
sattari [20]

Answer: The height of the building is 6.49 meters.

Step-by-step explanation:

This can be translated to:

"A building projects a 7.5 m shadow, while a tree with a height of 1.6 m projects a shadow of 1.85 m.

Which is the height of the building?"

We can conclude that the ratio between the projected shadow is and the actual height is constant for both objects, this means that if H is the height of the building, we need to have:

(height of the building)/(shadow of the building) = (height of the tree)/(shadow of the tree)

H/7.5m = 1.6m/1.85m

H = (1.6m/1.85m)*7.5m = 6.49m

The height of the building is 6.49 meters.

5 0
3 years ago
Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?
Aneli [31]
\frac{1}{x} +\frac{1}{y} = 5\\\\x^{-1}+y^{-1}=5\\

Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}

Now that we have dy/dx, we can plug in the x, which is 4, and the y, which is 4/19. We know these values of x and y because your question stated y(4) = 4/19.

\frac{dy}{dx}=-5(\frac{4}{19})^2-\frac{(\frac{4}{19})^2}{(4)^2}\\\\\frac{dy}{dx}=-5(\frac{16}{361})-\frac{(\frac{16}{361})}{16}\\\\\frac{dy}{dx}=\frac{-80}{361}-\frac{1}{361}\\\\\frac{dy}{dx}=\frac{-81}{361}
5 0
4 years ago
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