Answer:
Step-by-step explanation:
area=4×22/7×14²=4×22×28=2464 units²
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Answer:
Depth = 3.3 inches
Step-by-step explanation:
Given that the shape of the satellite looks like a parabola
The equation of parabola is given as follows
Where
a= 13
Therefore
Lets take (13 , y) is a
Now by putting the values in the above equation we get
y=3.25 in
Therefore the depth of the satellite at the nearest integer will be 3.3 inches.
Depth = 3.3 inches
You can simplify this expression with PEMDAS (parentheses, exponents, multiplication/division, addition/subtraction)
Start with the expressions in the parentheses:
4-7=-3
4+7=11
The expression now reads -2(-3)+5(11). Now, simplify the multiplication expressions:
-2*-3=6
5*11=55
The expression is 6+55 which is 61.
Hope this helps!!
