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3 years ago

15

You spend 264 on clothes. Shirts cost 24 and pants 32 you buy total of nine items write a system of linear equations that repres

ents this situation

1 answer:

yulyashka [42]3 years ago

7 0

The system of linear equation that represents this situation is:

$x+y=9\\24x+32y=264$

Step-by-step explanation:

The variables are used for creating system of equations

In the given scenario,

Let x be the number of shirts

and

y be the number of pants

Then,

"You spend 264 on clothes. Shirts cost 24 and pants 32"

24x+32y=264

"total of nine items"

x+y=9

The system of linear equation that represents this situation is:

$x+y=9\\24x+32y=264$

Keywords: Linear equations

Learn more about linear equations at:

#LearnwithBrainly

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What is 1.5 as a ratio

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Answer: 3/2

Step-by-step explanation:

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3 years ago

What is the solution of 9|2x – 1| + 4 < 49?

luda_lava [24]

Answer: $-2$

Step-by-step explanation:

You need to set up two cases (Positive case and negative case) and solve for "x".

- POSITIVE CASE IF: $2x-1>0$

$9(2x -1) + 4 < 49\\18x-9$

- NEGATIVE CASE IF: $2x-1$

$-9(2x -1) + 4 < 49\\-18x+9$

Therefore, the solution is:

$-2$

3 0

3 years ago

Read 2 more answers

100 POINTS PLZ HELP

crimeas [40]

An ordered pair such as (3,-1), is a shorthand way of writing two variables, such as x = 3 and y = -1. The order of the numbers in the pair is important: x always comes before y.

An ordered pair is a composition of the x coordinate (abscissa) and the y coordinate (ordinate), having two values written in a fixed order within parentheses.

It helps to locate a point on the Cartesian plane for better visual comprehension.

The numeric values in an ordered pair can be integers or fractions.

Ordered Pair = (x,y)

Where, x = abscissa, the distance measure of a point from the primary axis “x”

And, y = ordinate, the distance measure of a point from the secondary axis “y”

In the Cartesian plane, we define a two-dimensional space with two perpendicular reference lines, namely x-axis and y-axis. The point where the two lines meet at “0” is the origin.

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6 0

3 years ago

Read 2 more answers

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago

The problem is in the picture :)

frozen [14]

Answer:

Last option: 4

Step-by-step explanation:

The quadratic equation simplified: $x^2-4x=-\frac{7}{2}$ has the form:

$ax^2+bx=c$

In this case, you can identify that "a", "b" and "c" are:

$a=1\\b=-4\\c=-\frac{7}{2}$

To solve this quadratic equation by completing the square, Carlos should add $(\frac{b}{2})^2$ to both sides of the equation. This is:

$(\frac{-4}{2})^2=(-2)^2=4$

Then:

$x^2-4x+4=-\frac{7}{2}+4$

Therefore you can observe that the number he should add to both sides of the equation is: 4

8 0

3 years ago