Answer:

Step-by-step explanation:
By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other:
, or equivalently,
.
Given our linear equation 3x + y = 3 (or y = -3x + 3):
We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is
.
To test whether this is correct, we can take first slope,
, and multiply it with the negative reciprocal slope
:


Therefore, we came up with the correct slope for the other line, which is
.
Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

Okay, so since both y values share the same number, let's add both equations so the y values cancel out leaving us to solve for x.
10x+(-5x)=5x
7y+(-7y)=0
1+24=25
Now we have 5x=25
divide both sides by 5 and we have x=5
Now that we know x=5, we can plug it into one of the problems to find y.
Let's do 10(5) +7y=1
50+7y=1 subtract 5 and we get 7y=-49
divide -7 from both sides and we get y=-7
so there you have it x=5 and y=-7
It doesn’t represent a function, since in a function- the x values can’t repeat,
In (-13,4) and (-13,9) the x values are the same.