Answer:
B.
Step-by-step explanation:
I graphed it but you could also use the y intercept to determine which function matches the graph
log(x+1)<u>+3</u>
the +3 at the end of the function makes the y-intercept positive 3
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Y = mx + b
1.) -6x + y = 4
Move variable x over to the other side by adding 6x.
y = 6x + 4
2.) -y - 2x = 4
Move variable x over to the other side by adding 2x.
-y = 2x + 4
Divide the whole thing by -1 because y needs to be positive and alone.
y = -2x - 4
When x = 1 (that is x > 0) f(1) = 1^2 - 1 = 0
So b is correct
