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harina [27]
4 years ago
11

Theo started to solve the quadratic equation

Mathematics
1 answer:
STALIN [3.7K]4 years ago
8 0

Answer:

x + 2 =  \pm2

Step-by-step explanation:

After Theo added to both sides of:

{(x + 2)}^{2}  - 9 =  - 5

He got;

{(x + 2)}^{2} = 4

Next he took the square root of both sides to get;

x + 2 =  \pm \sqrt{4}

When Theo simplifies, he will obtain:

x + 2 =  \pm2

Therefore the second option is correct.

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Brandon is paid 150% of his regular hourly rate for overtime hours. He is paid \$45.00 an hour for overtime hoursWhat is his reg
Ne4ueva [31]

Answer:

Regular hourly rate for Brandon is $30

Step-by-step explanation:

Let the payment for regular hours be $x

given that

Brandon is paid 150% of his regular hourly rate for overtime hours

payment for overtime hours = 150% of payment for regular hours

payment for overtime hours = 150/100 * x = 3x/2

Given that He is paid \$45.00 an hour for overtime hours

thus,

3x/2 = 45

=> x = 45*2/3 = 30

Thus,  regular hourly rate for Brandon is $30

3 0
3 years ago
(d) estimate p(x < 1.5), i.e., the proportion of all thickness values less than 1.5. [hint: if you knew the values of μ and σ
Elan Coil [88]
<span>This question's solution is based on two context. First off, the probability of any events or occurrence cannot be greater than 1. If the question demands finding the probability that the proportion of all thickness (X) is less than 1.5 given the available data (mu and rho) then that would practically be impossible. It would only be feasible to ask, "if it were less than 1" My point is, suppose X is 1.3 which is actually less than 1.5, then we have a contradiction because our probability of occurrence or non-occurrence cannot be greater than 1.On the other hand suppose X is 0.2, then it will be pretty easy to input the formula to get valuable results.</span>
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%20%7D%5E%7B2%7D%20%3D%20%20%7B16%7D%5E%7Bx%3F%7D%20%20%20" id="TexFormula1" title=" {x
lora16 [44]
X is -1/2 . Using the Lambert W function.
x^2=16^x => x^2=(2^4)^x
x^2=2^4x => x=2^2x
x=(e^in(2))^2x => x=e^2in(2)x
e^2in(2)x1/x=1
xe^-2in(2)x=1 /*1
-xe^-2in(2)x=-1
-2in(2)xe^-2in(2)x=-2in(2)
W(-2in(2)xe^-2in2x)=W(-2in(2))
-2in(2)x=W(-2in(2))
X=-W(-2in(2))/2in(2)
5 0
3 years ago
In a certain sequence, each term, starting with the 3rd term, is found by multiplying the previous two terms. what is the differ
mina [271]
From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8. 

Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.

<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>
5 0
3 years ago
HELP<br> I NEED HELP ASAP
Leokris [45]

Answer:

Step-by-step explanation:

Jen: (1+2/3)x4 to find average (multiply by 4 to get 1 hour)

Jen's ave. is 3+2/3 mph

Max: (1.5)x5= average

Max's is 9 mph

Max is faster.

8 0
3 years ago
Read 2 more answers
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