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2 years ago

25 points to whoever solves the whole page

Mathematics

2 answers:

faust18 [17]2 years ago

8 0

Answer:

row 1

-9

-19

-13

row 2

-2

row 3

-3

-11

-7

Step-by-step explanation:

ryzh [129]2 years ago

8 0

Answer:

---

Step-by-step explanation:

1) 5

2) -7

3) -3

4) 4

5) 18

6) 15

7) -9

8) 25

9) -11

10) -10

11) 31

12) 37

13) 23

14) 42

15) -7

16) 2

17) -2

18) -3

19) -19

20) 23

21) 35

22) 18

23) 11

24) 3

25) 5

26) 23

27) -44

-hope it helps

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Answer:

Step-by-step explanation:

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3 years ago

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Andreas93 [3]

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Answer:

3 < b-a < 7

Step-by-step explanation:

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3 years ago

The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.

lorasvet [3.4K]

$p = 2w + 2l$ $p = 42$
$a = l * w$ $a = 108$

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2
$2's$ $cancel$ $out$
$\frac{p}{2} = w + l$

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
$\frac{p}{2} - l = w + l - l$
$l's$ $cancel$ $out$
p/2 - l = w

$a = l * w$

You replace w with the equation above p/2 - l = w
$a = l( \frac{p}{2} - l)$

Multiply out the L.
$a = \frac{p}{2}l - l^{2}$

Plug in all your numbers a = 110 and p = 42
$110 = \frac{42}{2}l - l^{2}$
$110 = 21l - l^{2$

Move everything to the left side so $l^{2}$ would be positive (makes the equation easier when $l^{2}$ is positive).
$l^{2} - 21l + 110 = 0$

Factor.
$(l -10)(l-11) = 0$

Make each parenthesis set equal to 0.
$l-11=0$ $l-10=0$

Add.
$l = 11$ $l = 10$

By doing this you solve for both the width and length so the answer is:
w = 11 L = 10

8 0

3 years ago