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3 years ago

12

a keycode must contain 2 letters and 3 numbers. the letters may be any letter of the alphabet. the numbers should be any number

from 0 to 9 how many different keycode combinations are there?

1 answer:

Rufina [12.5K]3 years ago

4 0

THERE ARE AT LEAST TWO KEY CODES

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What is the greatest common factor of 36x^3 and 8x

marusya05 [52]

Factor 36x^3 = (2)(2)(3)(3)(x)(x)(x)
Factor 8x = (2)(2)(2)(x)

Take what they have in common which is (2)(2)(x) and multiply and it will be 4x.

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3 years ago

When they arrived in Philadelphia, Tyler’s family took a taxi to a museum. The taxi charged $2.70 per mile, and they paid the dr

shtirl [24]

Answer:

5 miles

Step-by-step explanation:

To find how many miles it is from the train station to the museum we first have to subtract the tip from the total fair and you get 13.50 and then you divide 13.50 by 2.70 to get the number of miles and you get 5.

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2 years ago

Jody is buying a scrapbook and sheets of designer paper. She has $40 and needs at least $19.00 to

Bas_tet [7]

Answer:

7 sheets of paper

Step-by-step explanation:

$40-$19=$21

$21/$3=7 sheets of paper.

In words:

I did 40 minus 19 to get 21, and the divided 21 by 3 to get 7 sheets of paper.

8 0

2 years ago

Order these numbers from least to greatest.<br> 2<br> 12/5<br> 2.47<br> square root of 3

Arturiano [62]

Answer:

square root, 2,12/5,2.47

Step-by-step explanation:

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2 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

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2 years ago