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Snezhnost [94]
2 years ago
13

Write an equation that is perpendicular to y=3/5x-1 and passes through the point (9,14)

Mathematics
1 answer:
Leokris [45]2 years ago
8 0

Answer:

y=(-5/3)x+29

Step-by-step explanation:

we will use the base formula y=mx+b

In order to be perpendicular, the slope must be the flipped fraction and have the opposite sign, so our m is (-5/3)

y=(-5/3)x+b

You can plug in the (9,14) point in order to find the b

14=(-5/3)(9)+b

14=(-45/3)+b

14=(-15)+b

14+15=b

29=b

and so altogether our equation is y=(-5/3)x+29

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Which choice is the solution for this system ? 2x − 5y = 14 x + 3 2 y = 5
VashaNatasha [74]

Answer:

The required solution is (5.75,-0.5). It can be written as (\frac{11}{4},-\frac{1}{2}).

Step-by-step explanation:

The given equations are

2x-5y=14                       .... (1)

x+\frac{3}{2}y=5            .... (2)

Multiply the equation (2) by 2.

2x+3y=10                     .... (3)

Subtract equation (1) from equation (3).

2x+3y-(2x-5y)=10-14

2x+3y-2x+5y=-4

8y=-4

y=-\frac{1}{2}=-0.5

Put this value in equation (1).

2x-5(-0.5)=14

2x+2.5=14

2x=11.5

x=5.75

Therefore the required solution is (5.75,-0.5). It can be written as (\frac{11}{4},-\frac{1}{2}).

3 0
2 years ago
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