Write an equation that is perpendicular to y=3/5x-1 and passes through the point (9,14)

Mathematics

1 answer:

Leokris [45]3 years ago

8 0

Answer:

y=(-5/3)x+29

Step-by-step explanation:

we will use the base formula y=mx+b

In order to be perpendicular, the slope must be the flipped fraction and have the opposite sign, so our m is (-5/3)

y=(-5/3)x+b

You can plug in the (9,14) point in order to find the b

14=(-5/3)(9)+b

14=(-45/3)+b

14=(-15)+b

14+15=b

29=b

and so altogether our equation is y=(-5/3)x+29

You might be interested in

The graph of F(x), shown below, has the same shape as the graph of

timama [110]

If g(x) = -f(x), then the graph of g is obtained from the graph of f by reflecting about the x-axis. Suppose, for example, that f(2) = 3, so the point (2,3) is on the graph of f. Since g(x) = -f(x), then g(2) = -f(2) = -3, and the point (2,-3) is on the graph of g.

4 0

3 years ago

Read 2 more answers

Find an equation for the nth term in the following sequence:<br> 2, 8, 32, 128, 512...

seraphim [82]

Answer:

$a_n = 2(4) ^{n-1}$

Step-by-step explanation:

The sequence shown matches that of a geometric sequence of radius 4. To prove it, divide the term $\frac{a_{n + 1}}{a_n}$ and check that $\frac{a_{n + 1}}{a_n}=4$