All categories

3 years ago

John and Alan have a collection of x baseball cards. John has x/4 cards. What fraction of the cards does Alan have?

Mathematics

1 answer:

yulyashka [42]3 years ago

5 0

X-x/4
4x-x/4
3x/4
alan has 3x/4 cards.

You might be interested in

Eight friends are traveling together to the mountains one of them said he would pay for all the gas if they would each pay him b

saw5 [17]

The answer is 24.78 for each friend to pay

8 0

3 years ago

Can someone explain? And answer?

alexandr402 [8]

Answer:

$25.00

Step-by-step explanation:

You already know that $85 is an additional fee added to the monthly fees.

So, you first have to subtract 85 from $685 to get the total amount of monthly fees paid over 2 years.

685-85= 600

So, you can conclude that $600 is the total amount of monthly fees paid.

Now, you want to divide 600 by (the number of months in 2 years) to get the amount of monthly fees.

Since there is 24 months in 2 years you do:

600/ 24 which equals 25.

In conclusion, you can find that the monthly fee is $25.00.

6 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago

This is a math problem please help

givi [52]

Answer:

woah its me and my answer woah

3 0

2 years ago

Whats the answer pleaseeeee

Crazy boy [7]

The way calculate the volume is l*w*h, 3 times 5 times 7 is 105

Answer: D. 105 km^3

6 0

3 years ago