14 times 6 is 84, sorry if I didn’t understand your question
Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
Answer: f(2) = 6
Step-by-step explanation: In this problem, we are given the function
f (x) = (x + 1) 2 and we are asked to find f(2). In other words, if we put an "x" into our function, we get a (x + 1) 2 out.
f we put a 2 into the function, we get f(2) = (2 + 1) 2 out. Now all we have to do is simplify on the right side.
2 + 1 gives us 3 and if we multiply 3 by 2, we get a product of 6.
Therefore, f(2) is 6.
Answer:
There is a 90.32% probability that the cake was baked by Doug.
Step-by-step explanation:
We have these following probabilities:
A 70% probability that Doug bakes the cake.
A 30% probability that Jeremy bakes the cake.
A 40% probability that a cake baked by Doug gets a thumbs up.
A 10% that a cake baked by Jeremy gets a thumbs up.
One cake was selected at random on 10/01/2014 and got a "thumbs up".
1. Find the probability that the cake was baked by Doug.
The probability that a baked cake gets a thumbs up is:

Of those, 0.7*0.4 = 0.28 are baked by Doug.
So the probability is:

There is a 90.32% probability that the cake was baked by Doug.
Answer:
Question 1 Answer : x^2 - 2y^2
Question 2 Answer: x^2
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