Answer:
104 and 52
Step-by-step explanation:
just did the assignment on edgen
Answer:
Option (4). 25%
Step-by-step explanation:
The graph attached shows the exponential growth.
Let the graphed function is y =
Here 'r' = Rate of growth
t = Duration of time in years
y = enrollments after time 't' years
Graph shows at time 't' = 0 or initially number of enrollments = 20
After 8 years number of enrollments will be
120 = 

6 = 
log 6 = 
0.77815 = 
= 0.0972689


r = 25.1%
r ≈ 25%
Therefore, Option (4) will be the answer.
Answer:
83.85%
Step-by-step explanation:
We will use the empirical rule. For a standard normal distribution the mean is equal to 0 and the standard deviation is equal to 1. Then, between 3 standard deviations below the mean, we have 2.35% + 13.5% + 34% = 49.85% of data, and 1 standard deviation above the mean we have 34% of data. Therefore, the percentage of data that are between 3 standard deviations below the mean and 1 standard deviation above the mean is 49.85%+34% = 83.85%.
Answer:
P(G) = 0.55
the probability of getting an offspring pea that is green. Is 0.55.
Is the result reasonably close to the value of three fourths that was expected?
No
Expected P(G)= three fourths = 3/4 = 0.75
Estimated P(G) = 0.55
Estimated P(G) is not reasonably close to 0.75
Step-by-step explanation:
Given;
Number of green peas offspring
G = 450
Number of yellow peas offspring
Y = 371
Total number of peas offspring
T = 450+371 = 821
the probability of getting an offspring pea that is green is;
P(G) = Number of green peas offspring/Total number of peas offspring
P(G) = G/T
Substituting the values;
P(G) = 450/821
P(G) = 0.548112058465
P(G) = 0.55
the probability of getting an offspring pea that is green. Is 0.55.
Is the result reasonably close to the value of three fourths that was expected?
No
Expected P(G)= three fourths = 3/4 = 0.75
Estimated P(G) = 0.55
Estimated P(G) is not reasonably close to 0.75