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3 years ago

Aubrey can walk 4 1/2 miles in 1 1/2 hours. Find her average in miles per hour.

Mathematics

1 answer:

stepan [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Convert to improper fractions:

4 1/2 = 9/2

1 1/2 = 3/2

Find the reciprocal:

9/2 / 3/2 = 9/2 x 2/3

Multiply:

9/2 x 2/3 = 18/6

Simplify:

18/6 = 3

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What are the measures of Arc J K and ∠KIJ?

expeople1 [14]

Answer:

104 and 52

Step-by-step explanation:

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3 years ago

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∠A and ∠B are complements. If the measure of angle A=(8x-23) and the measure of angle B=(7x-7), then find the measure of ∠A

kap26 [50]

Answer:

Step-by-step explanation:

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3 years ago

Enrollment in a dance studio has grown exponentially since the studio opened. A graph depicting this growth is shown. Determine

denis23 [38]

Answer:

Option (4). 25%

Step-by-step explanation:

The graph attached shows the exponential growth.

Let the graphed function is y = $(1+\frac{r}{100})^{t}$

Here 'r' = Rate of growth

t = Duration of time in years

y = enrollments after time 't' years

Graph shows at time 't' = 0 or initially number of enrollments = 20

After 8 years number of enrollments will be

120 = $20(1+\frac{r}{100})^{8}$

$\frac{120}{20}=(1+\frac{r}{100})^{8}$

6 = $(1+\frac{r}{100})^{8}$

log 6 = $8\text{log}(1+\frac{r}{100})$

0.77815 = $8\text{log}(1+\frac{r}{100})$

$\text{log}(1+\frac{r}{100})$ = 0.0972689

$(1+\frac{r}{100})=1.251$

$\frac{r}{100}=0.251$

r = 25.1%

r ≈ 25%

Therefore, Option (4) will be the answer.

5 0

2 years ago

Solve the problem. For a standard normal distribution, find the percentage of data that are between 3 standard deviations below

solong [7]

Answer:

83.85%

Step-by-step explanation:

We will use the empirical rule. For a standard normal distribution the mean is equal to 0 and the standard deviation is equal to 1. Then, between 3 standard deviations below the mean, we have 2.35% + 13.5% + 34% = 49.85% of data, and 1 standard deviation above the mean we have 34% of data. Therefore, the percentage of data that are between 3 standard deviations below the mean and 1 standard deviation above the mean is 49.85%+34% = 83.85%.

7 0

3 years ago

In a genetics experiment on peas, one sample of offspring contained 450 green peas and 371 yellow peas. Based on those results

laiz [17]

Answer:

P(G) = 0.55

the probability of getting an offspring pea that is green. Is 0.55.

Is the result reasonably close to the value of three fourths that was expected?

Expected P(G)= three fourths = 3/4 = 0.75

Estimated P(G) = 0.55

Estimated P(G) is not reasonably close to 0.75

Step-by-step explanation:

Given;

Number of green peas offspring

G = 450

Number of yellow peas offspring

Y = 371

Total number of peas offspring

T = 450+371 = 821

the probability of getting an offspring pea that is green is;

P(G) = Number of green peas offspring/Total number of peas offspring

P(G) = G/T

Substituting the values;

P(G) = 450/821

P(G) = 0.548112058465

P(G) = 0.55

the probability of getting an offspring pea that is green. Is 0.55.

Is the result reasonably close to the value of three fourths that was expected?

Expected P(G)= three fourths = 3/4 = 0.75

Estimated P(G) = 0.55

Estimated P(G) is not reasonably close to 0.75

3 0

3 years ago