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Anuta_ua [19.1K]
2 years ago
13

The cylindrical container shown below can be completely filled with 24 litres of water. The base area of the container is 600 cm

2. What is the height of the container? PLEASE FAST!!​
Mathematics
1 answer:
Virty [35]2 years ago
5 0

Answer:

40cm

Step-by-step explanation:

volume of a cylinder= πr²h

V=24litres, Area=πr²=600cm², height=?

converting litres to cm³

1litre=1000cm³

24litres= 24×1000

=24000cm³

24000=600× h

h= 24000/600

= 40cm

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Answer:

  12\sin{(2\theta)}\cos{(\theta)}

Step-by-step explanation:

The appropriate trig identity is ...

  \sin{a}+\sin{b}=2\sin{\left(\dfrac{a+b}{2}\right)}\cos{\left(\dfrac{a-b}{2}\right)}

Here, you have a scale factor of 6 and a=3θ, b=θ. Filling in these values gives ...

  6\sin{3\theta}+6\sin{\theta}=12\sin{\left(\dfrac{3\theta+\theta}{2}\right)}\cos{\left(\dfrac{3\theta-\theta}{2}\right)}\\\\=12\sin{(2\theta)}\cos{(\theta)}

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2 years ago
What is 30% of $100?
lord [1]

Answer:

solution. :

30/100*$100

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6 0
2 years ago
In ΔBCD, \overline{BD}
Alex787 [66]

Answer:

30degrees

Step-by-step explanation:

Given

Exterior angle m<CDE = 7x - 19 degrees

interior angles are

m<BCD = 2x - 1

m<DBC = x+10

Since the sum of the interior angles is equal to the exterior, hence;

2x - 1 + x+10 = 7x - 19

3x + 9 = 7x - 19

3x - 7x = -19 - 9

-4x = -28

x = 28/4

x = 7

Get m<CDE

m<CDE = 7x - 19

m<CDE = 7(7) - 19

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8 0
2 years ago
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cricket20 [7]

Given Equation: \frac{1}{3}h-4(\frac{2}{3}h-3)=\frac{2}{3}h-6

Let us remove parenthesis first.

In order to remove parenthesis, we need to distribute -4 over parenthesis (2/3 h -3).

Distributing -4 over (2/3 h -3), we get,

-4*2/3 h - 4*-3 = -8/3 h + 12.

Substituting this value in original equation, we get

\frac{1}{3}h-\frac{8}{3}h+12 =\frac{2}{3}h-6

Now, in order to make the equation easy to solve, we always remove fractions. In order to remove fraction, we need to find the lowest common denominator of all terms(lcd).

The fraction terms has 3 in denominators, so we could multiply each and every term by 3 to remove 3's from denominators.

Multiplying each equation by 3, we get,

3*\frac{1}{3}h-3*\frac{8}{3}h+3*12 =3*\frac{2}{3}h-3*6

On simplfying this step, we get

1h -8h+36=2h-18

Combining like terms on left side, we get

-7h +36 = 2h -18.

Subtracting 36 from both sides, we get

-7h +36 -36= 2h -18-36.

-7h=2h-54

Subtracting 2h from both sides, we get

-7h-2h=2h-54-2h

-9h = -54

Dividing both sides by -9.

-9h/-9 = -54/-9

h = 6.

Therefore, final answer is h=6.


5 0
3 years ago
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