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AfilCa [17]
2 years ago
13

Divide. 52.98 ÷ 10³ Enter your answer as a decimal in the box. help!!!!!!!!

Mathematics
1 answer:
velikii [3]2 years ago
4 0

Answer:

0.05298

Step-by-step explanation:

If it wrong i'm sorry hope it helps

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<span>1. For the data in the table, does y vary directly with X? If it does write an equation for the direct variation.(X,y) (8,11) (16,22) (24,33) 
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Yes y=1.375x 

</span><span>2.for the data in the table, does y vary directly with X? If it does write an equation for the direct variation. (X,y) (16,4) (32,16) (48,36) 
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</span><span>3. (Time/hour,distance/miles)(4,233) (6,348) (8,464) (10, 580) 
Express the relationship between distance and time in a simplified form as a unit rate. Determine which statement correctly interprets this relationship. 
</span><span>58/1 your car travels 58 miles in 1 hour 

</span><span>4.what is the slope of the line that passes through the pair of points (2,5) and (8,3) 

</span>-1/3 

<span>4.what is the slope of the line that passes through the pair of points (-5.2,8.7) and (-3.2,2.7) 
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Y+5=-2/5(X+3) 

</span><span>8. Write an equation in point slope from for the line through the given point with the given slope. (4,-7) m=-0.54 

Y+7=-0.54(x-4) 

9. The table shows the height of a plant as it grows. Which equation in point slope from gives the plants height (time,plant height) (2,16)(4,32)(6,48)(8,64) 

Y-16=8(X-2)*** 
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2x+3y=21 



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X+2y=2 

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3 0
3 years ago
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Step-by-step explanation:

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On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
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Check the picture below.

since the vertical distance, namely the y-coordinate, is twice as much as the horizontal, then if the horizontal is "x", the vertical one must be 2x.

let's find the hypotenuse first.

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{x}\\ b=\stackrel{opposite}{2x}\\ \end{cases} \\\\\\ c=\sqrt{x^2+(2x)^2}\implies c=\sqrt{x^2+4x^2}\implies c=\sqrt{5x^2}\implies c=x\sqrt{5} \\\\[-0.35em] ~\dotfill

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

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3 years ago
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