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3 years ago

13

A circular trampoline has a

1 answer:

denpristay [2]3 years ago

6 0

Answer: A. 6.14 ft is the closes answer
(WORK SHOWN BELOW)

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A muffin recipe calls for 2/5 tablespoons of vanilla extract for 6 muffins. Arthur is making 18 muffins. How much vanilla extrac

GuDViN [60]

2/5 tablespoons of vanilla extract ... 6 muffins
x tablespoons of vanilla extract = ? ... 18 muffins

If you would like to know how much vanilla extract does he need, you can calculate this using the following steps:

x * 6 = 18 * 2/5
x * 6 = 36/5 /6
x = 36/5 / 6
x = 6/5 = 1 1/5

Result: Arthur will need 1 1/5 tablespoons of vanilla extract for 18 muffins.

7 0

4 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

4 years ago

Please help! I will give brainliest and 5 stars!

Ierofanga [76]

Answer:

(A.) x = y - 4

Step-by-step explanation:

All you need to do is subtract the 4 from both sides, giving you the final equation as x = y - 4.

7 0

3 years ago

Solve for x in the equation x2+2x+1= 17.<br> x=-1: V15<br> x=-11/17<br> X=-2=2.5<br> X=-11 13

Shalnov [3]

Answer:

x=-1

Step-by-step explanation:

x^2+2x=16=0

Use the quadratic formula to find the solutions.

−b±√b2−4(ac)/

2a

Substitute the values

a=1, b=2, and c=−16 into the quadratic formula and solve for x

4 0

4 years ago

Please help 3m+5=8 show workk

SashulF [63]

Step 1- Subtract 5 from both sides
3m = 8 - 5
Step 2- Simplify 8 - 5 to 3
3m = 3
Step 3- Divide both sides by 3
Answer: m = 1

3 0

4 years ago