The way to work it is to make a table in Excel (or equivalent program) with the data of budget for every year.
This is how it should look:
<span><span><span>year
budget
</span>
<span>
0
265.1
</span>
<span>
1
277.5
</span>
<span>
2
288.9
</span>
<span>
3
303.0
</span>
<span>
4
311.3
</span><span> 5
320.4
</span><span> 6
334.5
</span><span> 7
351.2
</span>
<span>
8
368.2
</span>
<span>
9 381.7
Select both columns and inser a scatter plot graph (menu, insert, graph, scatterplot).
Now change the design of the graph to include the model. In this case I got y = 12.724 x + 262.92
x represents the number of year after 1990 and y represents the budget.
Now you can use the model to calcualte the budget when you know the year and to calculate the year when you know the budget.
For year 2001, x = 11 and y = 12.724 (11) + 262. 92 = 402.88 (which is 402,880)
This is the same year for which the budget exceeds 400,000. </span></span></span>
Answer:
4x5x4x7x4x9x2x1x43x125
Step-by-step explanation:
Answer: A
Step-by-step explanation: once you line the numbers up in order from least the greatest, the two middle numbers will be 12. Add 12 + 12 and you get 24. Then divide it by 2 and get 12. That is your median. Your 1st quartile will be 10. Your second quartile will be 15. Your minimum number is 4 and your maximum number is 18.
Answer:
The expression is 8 x 5 + -26.
She now has 14 dollars.
We know that she paid 8 * 5 = $40, and we know that she got $26 back, so her net total of money she has is 40 - 26 = $14.
First u would out it in slope intercept form which would be y=2/3x+2 then u would graph it
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