Ax+ab=c; 2x2 = 9
Try to take it from there
Answer:
<h3>B 40</h3><h3>C 30</h3><h3>E 55</h3><h3>By the Triangle Inequality Theorem, the range of possible lengths of the third side is 0 < x < <u>28</u>.</h3><h3>So, the perimeter for all possible triangles must be greater than <u>28 units</u> and less than <u>56 units</u>.</h3>
Step-by-step explanation:
We are given an isosceles triangle has legs with length 14 units.
Therefore, another equal side would also be equal to 14 units.
Sum of two equal sides = 14+14 = 28 units.
Therefore, third sides would be less than 28 inches.
So, the perimeter of the triangle could be
28+28 = 56 that is less than 56 but greater than 28.
So, we could choose options B and C.
<h3>B 40</h3><h3>C 30</h3><h3>E 55</h3><h3>By the Triangle Inequality Theorem, the range of possible lengths of the third side is 0 < x < <u>28.</u></h3><h3>So, the perimeter for all possible triangles must be greater than <u>28 units</u> and less than <u>56 units.</u></h3>
The correct question is
Which is the graph of (x – 2)^2 + (y + 6)^2 = 4^2?
we have that
(x – 2)² + (y + 6)² = 4²
this is the equation of a circle with center at (2,-6) and radius r=4 units
the answer is
see the attached figure