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3 years ago

Help with this i dont understand

Mathematics

1 answer:

velikii [3]3 years ago

3 0

Answer:

a) 3/4

b) 3/4

c) 3/4

d) all are 3/4

Step-by-step explanation:

The slope of a line is defined as the change in y divided by the change in x. This is often referred to as "rise over run":

slope = Δy/Δx = "rise"/"run"

The triangles are drawn against the line so that you can use them to identify values of "rise" (vertical change) and "run" (horizontal change) between two points on the line.

The slope of the segment AC is found by dividing the "rise" (BC = 3) by the "run"(AB = 4)

slope of AC = BC/AB = 3/4

The slope of FH is similarly computed. Here, it is made a little more difficult, because you must estimate the value of GH.

slope of FH = GH/FG = 1.5/2 = 0.75 = 3/4

The slope of CE is ...

slope of CE = DE/CD = 6/8 = 3/4

The slopes in a), b), c) are all 3/4.

You can reasonably draw the conclusion that the slope of a line is the same everywhere. A line has constant slope.

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Math grades assignment unit test part 2 adding and subtracting rational numbers?

Katena32 [7]

Answer: When we add or subtract rational numbers that have the same denominator, we add or subtract only the numerators. The denominators stay the same. When we add or subtract rational numbers with unlike denominators, we need to change the rational numbers to equivalent rational numbers that have the same denominators, before we find the sum or difference. Adding & Subtraction Rational Numbers

Step-by-step explanation:

3 0

3 years ago

A and b are positive integers and a-b=2. Evaluate the following:<br> 9^1/2b/3^a

OlgaM077 [116]

Answer:

$\frac{1}{ 9 }$

Step-by-step explanation:

$\huge \frac{ {9}^{ \frac{1}{2}b } }{ {3}^{a} } \\ \\ = \huge \frac{ {( {3}^{2} )}^{ \frac{1}{2}b } }{ {3}^{a} } \\ \\ = \huge \frac{ { {3}}^{2 \times \frac{1}{2}b } }{ {3}^{a} } \\ \\ \huge = \frac{ {3}^{b} }{ {3}^{a} } \\ \\ \huge = \frac{1}{ {3}^{a - b} } \\ \\ \huge= \frac{1}{ {3}^{2} } \\ ( \because \: a - b = 2)\\ \\ \huge = \frac{1}{ 9 }$

5 0

3 years ago

Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom

IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0

3 years ago

jason and his family travels 160 miles in 3.2 hours. if they continue at this constant speed, how long will it take them to trav

Misha Larkins [42]

Set up a proportion
160 mi/ 3.2 hrs ≈ 300 mi/x hrs
cross multiply and solve for x and you get x≈6
It will take them 6 hours

3 0

3 years ago

Answer plzzz. Tell the truth and answer correctly

Free_Kalibri [48]

Answer:

54 feet

Step-by-step explanation:

We can use proportions

1 inch 27 inches

--------- = ------------

2 feet x feet

Using cross products

1x = 54

The building is 54 feet

3 0

3 years ago