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3 years ago

What are the first four terms of the sequence defined recursively below?

Mathematics

2 answers:

pogonyaev3 years ago

7 0

I think the answer is D hope this helps

Bezzdna [24]3 years ago

6 0

Answer:

Answer is D

Step-by-step explanation:

on edge

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Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

olga_2 [115]

Answer:

$7\pi cm^2$

Step-by-step explanation:

The area of a circle is given by $A=\pi r^2$

For circle B, the radius is 3 cm, it has an area of $\pi *3^2=9\pi cm^2$

Circle D also has a radius of 1 cm. Its area is $\pi *1^2=\pi cm^2$

Circle P also has a radius of 1 cm and area $\pi*1^2=\pi cm^2$

The area of the shaded region is then $9\pi -\pi-\pi=7\pi cm^2$

5 0

3 years ago

At what points does the helix r = left angle bracketsin(t), cos(t), tright angle bracket intersect the sphere x 2 + y 2 + z 2 =

r-ruslan [8.4K]

Answer:

the points are = (0.1045, 0.9945, 6) and ( -0.1045, 0.9945, -6)

Step-by-step explanation:

The detailed steps and appropriate substitution is as shown in the attached file.

4 0

3 years ago

What is the value of 4C9 ?

vekshin1

The answer is 0

The formula is

n!/ r!(n-r)!

4!/ 9!(4-9)!

7 0

2 years ago

Find -7a-6B (Picture provided)

sertanlavr [38]

Answer:

Option c

$-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

Then we perform operation -7A

$-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)$

Now we perform operation -6B

$-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)$

Now we add the resulting matrices

$\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

7 0

3 years ago

3c+2d=2;d=4 step by step

mina [271]

Hi there!

3c + 2d = 2 for d = 4
3c + 2(4) = 2
3c + 8 = 2
Subtract 8 to both sides
3c + 8 - 8 = 2 - 8
3c = -6
Divide both sides by 3
3c/3 = -6/3
c = -2

I hope I helped!

6 0

3 years ago