You need to find "two-fifths of 30." Of here means multiplication:
![\begin{aligned}\dfrac{2}{5}\cdot 30 &= \dfrac{2}{5}\cdot\dfrac{30}{1}\\[0.5em] &= \dfrac{60}{5}\\[0.5em] &= 12\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%2030%20%26%3D%20%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%5Cdfrac%7B30%7D%7B1%7D%5C%5C%5B0.5em%5D%20%26%3D%20%5Cdfrac%7B60%7D%7B5%7D%5C%5C%5B0.5em%5D%20%26%3D%2012%5Cend%7Baligned%7D)
There are 12 athletes in the club.
Answer: 13
Step-by-step explanation:
I used Pythagorean theorem to solve this problem. As DC and AD is 12 and 5, you would do 12²+5²= c². 12²= 144 and 5²= 25. 144+25= 169. It doesn't end there. Do the square root of 169 ---> √169=13.
I'm not sure what you want with the first part (3/1=6/2)
well PEMDAS or parenthasees exponents, mult or division whichever comes first, addition subtraction, whichever comes first so
3-1/1 would be divison first
1/1=1
3-1=2
24% of students I think
91 students out of 371
91/379=0.24
hoped this helped
Answer:
m% of n is mn/100.
Step-by-step explanation:
Begin with a concrete example: What is 5% of n?
To answer this, rewrite 5% as 0.05 and multiply n by this 0.05.
Now revert to m% of n: Divide m% by 100% and multiply n by this m/100.
m% of n is mn/100.
