Minimum value is equal to x=8, y=-4First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.Just plug in 8 to the original equation to find the answer for the minimum value.
The coordinates of C is, (3,-1)
A is the. Answer
Answer:
6x^2 (3x^2 - 2)
Step-by-step explanation:
18x^4 - 12x^2
6x^2 (3x^2 - 2)
