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frutty [35]
2 years ago
9

What is the range of the function g(x) = |x – 12| – 2?

Mathematics
1 answer:
s2008m [1.1K]2 years ago
4 0

your answer is {y | y > 12}

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Answer this please !
kompoz [17]

Answer:

x = 90°

Step-by-step explanation:

The diagonals of the kite AC and BD are perpendicular to each other

Hence x = 90°

6 0
3 years ago
Find two integers whose sum is -9 and product is -10
BigorU [14]

Step-by-step explanation:

if the two integers are x and y

xy=-10

x+y=-9

x+(-10/x)=-9

x2+9x-10=0

(x-1)(x+10)=0

x=1 or x=-10

if x=1, y=-10

if x=-10, y=1

so the two integers are 1 and -10

5 0
3 years ago
An equation is shown 0.58x?= 5.8 What is the value of missing number
Aleksandr-060686 [28]
You have to eat that
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Aliyah spent half of her weekly allowance playing arcade games. To earn more money her parents let her mow the lawn for $7. What
Fudgin [204]

Answer:

who mows the lawn for 7 dollars :/

Step-by-step explanation:

4 0
3 years ago
A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili
Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

18x = 3*31

x = \frac{31*3}{18}

x = 5.17

So \mu = 5.17

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

P(X \leq 3) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057

P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294

P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760

P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242

Finally

P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0
4 years ago
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