<span>Formula for exponential decay is:
N = No * e^-kt
N = 1/2(45) = 22.5
No = 45
k = 0.1109
The solution to your problem is as follows:
Let's try to solve the half-life if it is 45 grams, after which, you will now have an idea on how to solve the problem.
22.5 = 45 * e^(-0.1109t)
1/2 = e^(-0.1109t)
ln(1/2) = -0.1109t
t = (ln(1/2))/(-0.1109) = 6.25 days
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:
62.5%
Step-by-step explanation:
10x100 divded by 16 =62.5
X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
Answer:
a or d im very positive that is d
Step-by-step explanation:
Answer:
a) r = 0.974
b) Critical value = 0.602
Step-by-step explanation:
Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below
Test A | 64 48 51 59 60 43 41 42 35 50 45
Test B | 91 68 80 92 91 67 65 67 56 78 71
To find - (a) What is the value of the linear coefficient r ?
(b) Assuming a 0.05 level of significance, what is the critical value ?
Proof -
A)
r = 0.974
B)
Critical Values for the Correlation Coefficient
n alpha = .05 alpha = .01
4 0.95 0.99
5 0.878 0.959
6 0.811 0.917
7 0.754 0.875
8 0.707 0.834
9 0.666 0.798
10 0.632 0.765
11 0.602 0.735
12 0.576 0.708
13 0.553 0.684
14 0.532 0.661
So,
Critical r = 0.602 for n = 11 and alpha = 0.05
